A 4.19-F and a 7.46-F capacitor are connected in series across a 35.0-V battery. A 8.46-F capacitor is then connected in parallel across the 4.19-F capacitor. Determine the voltage across the 8.46-F capacitor.

Answer 1

so now you have 12.64-F in series with a 7.46.

Because the two equivalent series C have the same charge, voltage divides then to give across the indicated capacitor branch as

C=Q/V or VC=Q ,or v is inversely proportional to C because both branches have the same q.

V=35*12,64/(12.64+7.46)