m₁a=m₁g -T
m₂a=m₂g-T
a(m₁-m₂)=g(m₁+m₂)
a =g(m₁+m₂)/(m₁-m₂)= ...
A 2kg and a 4kg hang freely at opposite ends of a light inextensible string which passes over a small and light pulley fixed to a rigid support calculate the acceleration of the system
2 answers
3.3
4 answers