Ask a New Question

A+2B--->2C Kc=2.27

2c--->D Kc=0.144

Calculate the equilibrium constant for the reaction
D--->A+2B

1 answer

Add eqn 1 to eqn 2 to obtain
A+2B ==> 2C
2C ==> D
------------
A + 2B ==> D so K' = k1*k2.
You want the reverse of this rxn; therefore, you want 1/K'.

Ask a New Question or answer this question.

Similar Questions

In the industrial synthesis of ammonia, the equilibrium constant expression may be written as: Keq= [NH3]^2/[N2][H2]^3Calculate
1. 2 answers
The equilibrium constant Kc for the following reaction is equal to 0.20 at 250°C. Calculate the equilibrium constant Kp for the
1. 1 answer
given the equilibrium constant for the following reaction at 500 K,2 NO (g) + O2 (g) <==> 2 NO2 (g) Kc = 6.2x10^5 calculate the
1. 2 answers
The equilibrium constant Kc for the following reaction is equal to 0.20 at 250°C. Calculate the equilibrium constant Kp for the
1. 1 answer

more similar questions