given the equilibrium constant for the following reaction at 500 K,

Question

2 NO (g) + O2 (g) <==> 2 NO2 (g) Kc = 6.2x10^5
calculate the equilibrium constant for the reaction expressed as partial pressures, Kp.

the answer is 1.51x10^4. How do i get this?

Answer 1

Kp = Kc(RT)^{delta n}
delta n = nproducts-nreactants.

Answer 2

hhk