nvm I figured it out...
the answer was -1.6*10^-2 m
A 265g mass attached to a horizontal spring oscillates at a frequency of 1.00Hz . At t =0s, the mass is at x= 4.20cm and has vx = − 1*.0cm/s. Determine the position at t= 3.60s.
So I already found that...
The period is 1.0000 s
The angular frequency is 6.2832 rad/s
The amplitude is 5.1753×10^−2 m
The phase constant is 0.6240 rad
The maximum speed is 0.325 m/s
The maximum acceleration 2.04 m/s^2
The total energy is 1.40×10^−2 J
The position at t= 3.60 s is….????
2 answers
Youve got the wrong amplitude