A .25 kg skeet is fired at an angle of 30 degrees to the horizon with a speed of 30 m/s, When it reaches the maximum height, a 15 g pellet hits it from below. Before the collision, the pellet was traveling vertically upward at a speed of 200 m/s Embedded in the skeet, the two move together after the collision.

Question

a) How much higher did the skeet go up?
b) How much distance does the skeet travel because of the collision?

Answer 1

For A-

m1v1 = m2v2
(.015kg + .25kg)V = .015kg + 200m/s
v = 11.3m/s
(1/2)mv^2 = mgh so h=(1/2)(v^2)/g
h = 6.5m