A 25 kg box is along a horizontal floor and a force of 400 N pushes the box with an angle of 50 deg with the horizontal. Starting from rest, the box achieves a velocity of 2 m/s in a time of 4 seconds. Find the coefficient of sliding friction between box and the floor.

Answer 1

break the pushing force into vertical and horizonal components, Fv, Fh

Fv=400sin50
Fh=400cos50

Now, write the force equation
forcetotal=ma
fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
a=changevelocity/time=2/4 m/s^2=.5m/s^2

Answer 2

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Answer 3

What would be the weight of the box?

Answer 4

If it were not given