376 - 214 = F
F = m a
so
a = F/90.8
t = 3 s
v = a t = 3 a
x = 0 + 0 + (1/2) a t^2 = 4.5 a
A box which has a mass of 90.8kg is at rest on a rough horizontal floor, A man pushes on the box with a horizontal force of 376N. As soon as the box begins to move a friction force of 214N acts on the box from the floor.
a. What is the acceleration of the box while the man is pushing it?
b. What is the position of the box at the end of an interval of 3.00s? (assume x₀ = 0)
c. If the man stops pushing the box at the end of the 3.00s time interval, what is the acceleration of the box as the box comes to a stop?
1 answer