A 25 g bullet with a muzzle velocity of 300 m/s is fired into a board 4.0 cm thick. A). In a hard board, the bullet penetrates 3.0 cm and comes to a stop. What is the average force exerted on the bullet by the board?

Question

A 25 g bullet with a muzzle velocity of 300 m/s is fired into a board 4.0 cm thick. A). In a hard board, the bullet penetrates 3.0 cm and comes to a stop. What is the average force exerted on the bullet by the board?
B). For a soft board, the bullet goes through the board and emerges with a speed of 50 m/s. What was the average force exerted on the bullet by the board.
Answers:
A= 37,500 N
B= 27344 N
Show work

Damon · Answer

momentum = m v = .025 * 300

stops in .03 meters

average speed during stop = 150 m/s

time to stop = .03 meters/150 m/s

force = change in momentum/time
= .025 * 300 / (.03/150)

= 37,500 N

do B the same way

Reed · Answer

Maybe you should read the book to find out.

Atheist Chad · Answer

Maybe we could just get rid of guns... ¯\_(ツ)_/¯