A 240 kg roller coaster car Rolls over the crest of the roller coaster with a speed of 2.2m/s.if it falls through a vertical height of 12m down the tracks to the bottom of a trough, how fast will it be travelling?
So here's what I did but I don't think it's right:
Eg=mgh
=240x9.8x12
=28224J
Ek=(1/2)(240)(2.2)
=264J
EM=ek+eg
=28488
So I assumed that h=0 at the bottom of the trough
Eg=9.8x0x240
=0
So therefore ek=28489
28488J=1/2(240)v^2
15.4m/s=v
I'm not sure if this is actually correct?? Thank you so much
2 answers
looks actually correct to me
“Ek=(1/2)(240)(2.2)
=264J”
This is wrong. Ek = 1/2mv SQUARED. Not 1/2mv.
=264J”
This is wrong. Ek = 1/2mv SQUARED. Not 1/2mv.
0 answers