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A 230.-mL sample of a 0.280 M CaCl2 solution is left on a hot plate overnight; the following morning, the solution is 1.10 M. What volume of water evaporated from the 0.280 M CaCl2 solution?

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230mL of .280M solution contains 0.0644 moles CaCl2

x L of 1.1M solution now contains the .0644 moles, so x = 0.0585 = 58.5 mL

so, subtract to find the difference, which evaporated.
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