A 2200. Kg vehicle is traveling at 26 m/s what is the force needed to stop it in 21 seconds?

Answer 1

change in velocity = 0 -26 = -26m/s

change in time = 21s

so
a = change in velocity/change in time
= -26/21

F = m a = 2200 (-26/21) Newtons

Answer 2

V = Vo + a*t = 0.
26 + a*21 = 0,
a = -1.24 m/s^2.

F = M*a = 2200 * (-1.24)

Answer 3

post it.