Vehicle A is 819.017 feet behind vehicle B. Vehicle A is traveling at 93.602fps and vehicle B is traveling at 44fps. How long until vehicle A catches vehicle B?

Answer 1

so the 2nd vehicle must make up the distance of 819.017 ft
let the time taken to catch up be t seconds

93.602t - 44t = 819.017
solve for t

Answer 2

in time t
vehicle A travels distance d
vehicle B travels distance (d-819.017)

93.602 t = d

44 t = d-819.017

so
44 t = 93.602 t -819.017