F=Fx+Fy
Two equations:
1.)
Fx=F*Sin35=m*v^2/r
2.)
Fy=F*Cos35-Fg
Fy=F*Cos35-m*g
Solve equation 2 for F:
m*g=F*Cos35
Solving for F:
mg/Cos35=F
Plug 2 into 1 and simplify:
(mg/Cos35)*Sin35=m*v^2/r
mg*Tan35=m*v^2/r
Masses cancel:
g*Tan35=v^2/r
Solve for v:
sqrt[r*(g*Tan35)]=v
Use the last equation, I think.
And plug in the following:
g=9
r=0.86m
Tan35=0.7 *** I think
A 22 g ball is fastened to one end of a string
86 cm long and the other end is held fixed at
point O so that the string makes an angle of
35
◦
with the vertical, as in the figure. This
angle remains constant as the ball rotates in
a horizontal circle. The angle
θ
would remain
constant only for a particular speed of the ball
in its circular path.
The acceleration of gravity is 9
Find the velocity
1 answer