A 22.0 g piece of aluminum at 0.0°C is dropped into a beaker of water. The temperature of the water drops from 92.0°C to 77.0°C. What quantity of heat energy did the piece of aluminum absorb?

Question

Please Help, I'm so lost :(
Thank you

Answer 1

heat gained by the Al + heat lost by the water = 0\

heat lost by water = q
q = mass water x specific heat water x (Tfinal-Tinitial).