A 2115 kg car moving east at 10.61 m/s col- lides with a 3169 kg car moving north. The cars stick together and move as a unit after the collision, at an angle of 32.4◦ north of east and at a speed of 5.03 m/s.

What was the speed of the 3169 kg car before the collision?

1 answer

original east momentum = 2115*10.61
final east momentum
= (2115+3169)*5.03cos32.4

22440 = 5284 * 4.25 v = 22440 v

v =1 m/s