A 20kg box rests ona table and a 10kg is placed on top of the 20kg box. Determine the normal force that the table exerts on the 20kg box and the normal force that the 20kg box exerts on the 10kg box.

Question

please help

Answer 1

a. Fn = (m1+m2)*g = (10+20)*9.8 = 294 N.

b. Fn = m1*g = 10 * 9.8 = 98 N.