Asked by Jill

Four boxes of various masses are placed on a friction
free table. Rank these boxes according to net force
by listing them in order from greatest to least.

A) <-5N--| 5 kg |--10N->

B) <-10N--|10kg|-15N-->

C) <-10N--|5kg|-15N-->

D) <-5N--|20kg|-15N-->

Thank You :)
(the |_ kg | are the boxes)
=)

Answered by drwls
With no friction, the mass in the box will not affect the net force.

D) will have a net force of 10 N to the right. All of the other three will have a net force of 5 N to the right. They would be "tied"
Answered by Jill
I apologize I forgot to add: which has the most force to the right?
will this still affect the answer?

Thank You

~Jill :]
Answered by drwls
If you read my answer (D), it will answer your latest question.
Answered by Jill
Ok thank you :) I didn't see the rest of the answer because it went off the page, thank you so much for your help! :)
Answered by eajofjdoiwaj
What if box D is 15 kilos?
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