Asked by Jill
                Four boxes of various masses are placed on a friction
free table. Rank these boxes according to net force
by listing them in order from greatest to least.
A) <-5N--| 5 kg |--10N->
B) <-10N--|10kg|-15N-->
C) <-10N--|5kg|-15N-->
D) <-5N--|20kg|-15N-->
Thank You :)
(the |_ kg | are the boxes)
=)
            
            
        free table. Rank these boxes according to net force
by listing them in order from greatest to least.
A) <-5N--| 5 kg |--10N->
B) <-10N--|10kg|-15N-->
C) <-10N--|5kg|-15N-->
D) <-5N--|20kg|-15N-->
Thank You :)
(the |_ kg | are the boxes)
=)
Answers
                    Answered by
            drwls
            
    With no friction, the mass in the box will not affect the net force. 
D) will have a net force of 10 N to the right. All of the other three will have a net force of 5 N to the right. They would be "tied"
    
D) will have a net force of 10 N to the right. All of the other three will have a net force of 5 N to the right. They would be "tied"
                    Answered by
            Jill
            
    I apologize I forgot to add: which has the most force to the right?
will this still affect the answer?
Thank You
~Jill :]
    
will this still affect the answer?
Thank You
~Jill :]
                    Answered by
            drwls
            
    If you read my answer (D), it will answer your latest question.
    
                    Answered by
            Jill
            
    Ok thank you :) I didn't see the rest of the answer because it went off the page, thank you so much for your help! :)
    
                    Answered by
            eajofjdoiwaj
            
    What if box D is 15 kilos?
    
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