A 200 gram sample of hot water at 89°C is mixed with 200 grams of cool water at 16°C. Assume there is no loss of heat energy to the surroundings, what is the final temperature of the mixture when they reach thermal equilibrium?

Answer 1

the sum of heats gained is zero.

200(cw)(tf-89)+200(cw)(Tf-16)=0

2tf=89+15
tf= 52C