Asked by Anonymous
A 30.0 gram sample of water at 280. K is mixed with 50.0 grams of water at 330. K. Calculate the final temperature of the mixture assuming no heat loss to the surroundings.
Answers
Answered by
DrBob222
heat gained by cold water + heat lost by hot water = 0
mass1 H2O x specific heat water x (Tfinal-Tinitial)] + [mass2 H2O x specific heat water x (Tfinal-Tintial)] = 0
mass1 H2O x specific heat water x (Tfinal-Tinitial)] + [mass2 H2O x specific heat water x (Tfinal-Tintial)] = 0
Answered by
Bob the Builder
Your mother
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