Asked by Kat
A 200 gram sample of hot water at 89°C is mixed with 200 grams of cool water at 16°C. Assume there is no loss of heat energy to the surroundings, what is the final temperature of the mixture when they reach thermal equilibrium?
Answers
Answered by
bobpursley
the sum of heats gained is zero.
200(cw)(tf-89)+200(cw)(Tf-16)=0
2tf=89+15
tf= 52C
200(cw)(tf-89)+200(cw)(Tf-16)=0
2tf=89+15
tf= 52C
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