a) T = 2pi / w so w = 2 pi / T
w = sqrt ( k / m )
so k = w² / m
b) (1/2)* k * xmax ² = 2,00 J
so, xmax = sqrt( 2,00 * 2 / k)
A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.00 J, find
(a) The force constant of the spring and
(b) The amplitude of the motion.
2 answers
Actually for part a it's;
k=w^2*m
k=w^2*m
2 answers