a 20 kg loudspeaker is suspended 2m below a ceiling by two 3m-long cables that angle outward at equal angles. what is the tension in the cables?

Answer 1

The amount of angle is important.

Use symettry, each cable is holding half the weight.

measuring the angle between the vertical and the cable, then 1/2 mg=Tension*cosTheta where theta is from the vertical to a cable.

Answer 2

i got the answer by
(2m/3m)=0.666
sin-1(0.666)=41.8 degrees
to find tension
T=Fg/2sin(theta)
20kg*9.8=196N
2sin(41.8)=1.333
196N/1.3333=147N

Answer 3

jkj;l