A 2.50 l gas cylinder is filled with neon gas at a pressure of 36.5 ATM and a temperature of 19°C how many grams in neon are in the cylinder

Answer 1

To calculate the number of grams of neon gas in the cylinder, we first need to convert the given values into appropriate units.

1. Convert the temperature from Celsius to Kelvin:
T(K) = 19°C + 273 = 292 K

2. Use the ideal gas law equation to calculate the number of moles of neon gas in the cylinder:
PV = nRT
Where:
P = pressure (in ATM)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)

Substitute the values:
36.5 ATM * 2.50 L = n * 0.0821 L.atm/mol.K * 292 K

n = (36.5 ATM * 2.50 L) / (0.0821 L.atm/mol.K * 292 K) ≈ 89.16 moles

3. Calculate the molar mass of neon gas:
The molar mass of neon gas (Ne) is 20.18 g/mol.

4. Calculate the mass of neon gas in the cylinder:
mass = number of moles * molar mass
mass = 89.16 moles * 20.18 g/mol ≈ 1801.09 grams

Therefore, there are approximately 1801.09 grams of neon gas in the cylinder.