a 2.0kg object is pulled horizontally by a force of 6.3N along the floor where the coefficient of kinetic friction is o.24. what is the object acceleration

Answer 1

Wo = mg = 2kg * 9.8N/kg = 19.6 N. = Wt.
of the object.

Fo = 19.6 N @ 0 Deg.
Fp = 19.6*sin(0) = 0 = Force parallel
to floor.
Fv = 19.6*cos(0) = 19.6 N. = Force perpendicular to floor.

Fn = Fap - Fp - u*Fv,
Fn = 6.3 - 0 - 0.24*19.6 = 1.6 N. = Net
force.

a = Fn / m = 1.6 / 2 = 0.80 m/s^2.