a 20 kg traveler's bag is being pulled along the floor with a force of 50 NF. the force is applied on the handle forming an angle of 30 degree with the horizontal. neglecting friction,what is the acceleration og the bag? How much force is exerted by the floor on the bag?

Answer 1

M*g = 20 * 9.8 = 196 N.=Wt. of suitcase.

a. a = Fx/M = 50*cos30/20 = 2.17 m/s^2.

b. Fn = 196 - 50*sin30 = 171 N.=Normal
force = Force exerted on the bag by the
floor.

Answer 2

NONE

Answer 3

2.17 m/s^2