Using x y coordinates: i is unit x vector, j is unit y vector
original momentum = -1971*16.4 i - 4170 * 9.4 j
= -32324 i - 39198 j
final momentum = 6141 Vx i + 6141 j
so
Vx = -32324/6141 = -5.26 or 5.26 m/s west
Vy = -39198/6141 = -6.38 or 6.38 m/s south
A 1971 kg Oldsmobile traveling west on Saginaw Street at 16.4 m/s is unable to stop on the ice covered intersection for a red light at Abbott Road. The car collides with a 4170 kg truck hauling animal feed south on Abbott at 9.4 m/s. The two vehicles remain locked together after the impact. Calculate the velocity of the wreckage immediately after the impact. Give the speed for your first answer and the compass heading for your second answer. (remember, the CAPA abbreviation for degrees is deg)
2 answers
v = sqrt (5.26^2+6.38^2)
tan angle south of west = 6.38/5.26 = 1.2
so angle s of w = 50.2
so heading = 270 - 50.2 = 220
tan angle south of west = 6.38/5.26 = 1.2
so angle s of w = 50.2
so heading = 270 - 50.2 = 220
2 answers