friction=mgh-1/2 m v^2
= m(gh-.5 v^2)=16(9.8*2.5-.5*2.25^2)
=352 Joules
A 16.0 - kg descends a slide 2.50 m high and reaches the bottom with a speed of 2.25 m/s. How much thermal energy due to firciton was generated in the process?
for this I keep on getting 432.5 J but the back of the book tells me that the answer is 352 J and I do not see how to get this answer
I did the PE at the the top of the slide minus the KE at the bottom and got 432.5 J apparently I'm doing soemthing wrong thanks
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