The change in heat content in the system can be calculated using the specific heat capacity of water. The specific heat capacity of water is 4.184 J/g°C. Therefore, the change in heat content in the system is:
Change in heat content = (152 g)(4.184 J/g°C)(0°C - (-37°C)) = 11416.72 J
A 152 g sample of ice at –37 degree C is heated until it turns into liquid water at 0 degree C. How do you find the change in heat content in the system?
I've found H(I) [Change in heat of the ice] to be 11416.72 but im still stuck on the change of heat for the water.
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