An 80.0 g sample of a gas was heated from 25 degree C to 225 degree C. During this process, 346 J of work was done by the system and its internal energy increased by 7495 J. What is the specific heat of the gas?

Question

J/(g∗C)

Answer 1

I believe this is
E2-E1 = delta E = q+w
dE = 7495
w is -346
q = 7495+346 = ?
Then q = mass gas x specific heat gas x (Tfinal-Tinitial)
Solve for specific heat gas.

Answer 2

you did not solve the whole problem!