force = change in momentum /change in time
= .015 (715/2.5)10^3 = 4.29 *10^3 = 4290 N
a 15-g bullet is fired from a rifle. it takes 2.50 * 10^-3s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet. (answer 4290 N)
2 answers
Hey bots, you sure made that look hard.
What Newton actually said for his second law was force = rate of change of momentum.
that is change in (m V) / change in time or F = dP/dt
if m is constant it is m * dV / dt or F = m A ( the simple physics 1 way but watch out for special relativity)
However I did this in one short line by using the real thing, Force =- rate of change of momentum
What Newton actually said for his second law was force = rate of change of momentum.
that is change in (m V) / change in time or F = dP/dt
if m is constant it is m * dV / dt or F = m A ( the simple physics 1 way but watch out for special relativity)
However I did this in one short line by using the real thing, Force =- rate of change of momentum
3 answers