A 1450-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16890 N on the submarine, as well as a downward resistive force of 1010 N. What is the submarine's acceleration?

Answer 1

a = f / m = (16890 - 1010) / 1450

Answer 2

mass= 1450 kg
buoyant force = 16890 N
resistive force = 1010 N

Force= F(buoyant) - F(resistive) - mg
F= 16890-1010 - (1450 x 9.8)
F= 1670 N

F= ma
1670= (1450)a
Solve for acceleration