A 1420-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16930 N on the submarine, as well as a downward resistive force of 1030 N. What is the submarine's acceleration?
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Lets the upward and downward forces be F1 and F2 respectively,F=F1-F2,16930-1030=15900N...using F=ma....Make a the subject of formula by dividing both sides by m,to give a=F/m..15900/1420..a=11.197m/s2
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