A 1300 kg El Camino is parked on a 20 degree hill.(20 degrees above x axis)The driver of the El Camino returns, starts the car, and accelerates up the hill at 2 m/s^2. Find Sigma-Fx and Sigma-Fy. What is the normal Force acting on the car, and what is the force being supplied by the engine pushing the car up the hill?

Answer 1

You do not say what directions are x and y

gravity force down = m g = 1300 * 9.81

component of gravity force normal to road = m g cos 20
that is balanced by force up from road normal to road, no acceleration normal to road

Component of gravity force down slope
= m g sin 20

force up slope from engine (actually from road friction on tires)
= F

total force up road parallel to road
= F - m g sin 20

force = mass * acceleration
F - m g sin 20 = m a = 1300* 2 = 2600
so
F = 1300*9.81 *sin 20 + 2600