A 125-newton box rests on a plank 3.00 meters long, one end of which is 1.00 meters higher than the other end. Find the components of the force the box exerts

Parallel to the inclined plane=

Perpendicular to the inclined plane=

1 answer

The plank is inclined
A = sin^-1 1/3 = 19.5 degrees.

Weight force parallel to plane:
125 N*sin A = 41.7 N

Perpendicular to plane:
125 N*cosA = 117.9 N