Asked by john
A 125-newton box rests on a plank 3.00 meters long, one end of which is 1.00 meters higher than the other end. Find the components of the force the box exerts
Parallel to the inclined plane=
Perpendicular to the inclined plane=
Parallel to the inclined plane=
Perpendicular to the inclined plane=
Answers
Answered by
drwls
The plank is inclined
A = sin^-1 1/3 = 19.5 degrees.
Weight force parallel to plane:
125 N*sin A = 41.7 N
Perpendicular to plane:
125 N*cosA = 117.9 N
A = sin^-1 1/3 = 19.5 degrees.
Weight force parallel to plane:
125 N*sin A = 41.7 N
Perpendicular to plane:
125 N*cosA = 117.9 N
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