The force from the car on the truck = 4420 - 1230 a
So our task is to find a
total m = 1230 + 2180 = 3410 kg
total F = 4420 - 750 = 3670 N
so
a = 3670/3410 = 1.08 m/s^2
so finally
F on truck = 4420 - 1230 (1.08)
F on truck = 3096 Newtons
A 1230 -kg car is pushing an out-of-gear 2180 -kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push horizontally against the ground with a force of 4420N . The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 750N , including the "friction" of turning the truck's drivetrain. What is the magnitude of the force the car applies to the truck?
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1 answer