A 900 kg car pushes a 1900 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4800 N.

Question

(a) What is the magnitude of the force of the car on the truck?
(b) What is the magnitude of the force of the truck on the car?

Answer 1

F = m a
4800 = (900+1900) a
a = 4800/2800 = 1.714 m/s^2

a)
F = m a
F = (1900)(1.714)
= 3257 Newtons

b)
negative 3257 Newtons (action and reaction)

Answer 2

The sled dog in figure drags sleds A and B across the snow. The coefficient of friction between the sleds and the snow is 0.10.

Answer 3

The first answer posted by Damon is correct, but part B is not, since the problem is an action-reaction pair, the forces will be the same, thus part B is the same answer as part A