Asked by john
A 12 g sample of Ne is added to a container that also holds .78 mol of helium gas. What is the partial pressure of helium if the total pressure, after mixing is 2.43 atm?
Answers
Answered by
DrBob222
mol He = 0.78
mols Ne = grams/molarmass
total mols = nHe + nNe.
pHe = XHe*Ptotal
pNe = XNe*Ptotal
Ptotal = 2.43 atm.
mols Ne = grams/molarmass
total mols = nHe + nNe.
pHe = XHe*Ptotal
pNe = XNe*Ptotal
Ptotal = 2.43 atm.
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