A 12.0 V battery delivers a 0.40 A current to an electric motor that is connected across the battery terminals. How much electric energy is delivered in 500 seconds?

Group of answer choices

600 Joules

1,200 Joules

4,800 Joules

2,400 Joules

1 answer

To calculate the electric energy delivered, we can use the formula for electrical energy:

\[ \text{Energy} = \text{Power} \times \text{Time} \]

First, we need to calculate the power (in watts) delivered by the battery. The power can be calculated using the formula:

\[ \text{Power} = \text{Voltage} \times \text{Current} \]

Given:

  • Voltage (V) = 12.0 V
  • Current (I) = 0.40 A

Now we calculate the power:

\[ \text{Power} = 12.0 , \text{V} \times 0.40 , \text{A} = 4.8 , \text{W} \]

Next, we can find the energy delivered over 500 seconds. Using the energy formula:

\[ \text{Energy} = \text{Power} \times \text{Time} \]

Substituting the known values:

\[ \text{Energy} = 4.8 , \text{W} \times 500 , \text{s} = 2400 , \text{J} \]

Thus, the electric energy delivered in 500 seconds is 2,400 Joules.

The correct answer is:

2,400 Joules