1000*9.8 = 9800 Newtons weight
Force up from cable = T sin 35
force up from cable = weight down
T sin 35 = 9800
A 1000kg load is suspended from the end of a horizontal boom. The boom is supported by a cable that makes an angle of 35deg with the boom.
a) what is the tension in the cable?
b) what is the horizontal force on the boom?
2 answers
Force inward from tension = T cos 35
= 9800 cos 35/sin 35
which is the horizontal compression force on the boom.
= 9800 cos 35/sin 35
which is the horizontal compression force on the boom.
2 answers