heat gained by water equals heat lost by metal
50.0 * (t - 20.0) * 4.182 =
... 1000 * (100.0 - t) * 0.50
A 1000 g sample of metal with a specific heat of 0.50 J/goC is heated to 100.0oC and then placed in a 50.0 g sample of water at 20.0oC. (Hint: Specific heat of water at 20.0oC is 4.182 J/goC). What is the final temperature of the metal and the water? Write your answer to the correct number of significant figures in scientific notation.
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