heat lost by hot metal + heat gained by water = 0
[(mass metal x specific heat metal x (Tfinal-Tinitial)] + [(mass H2O x specific heat H2O x (Tfinal-Tinitial)]=0
Substitute the numbers and solve for the only unknown in the equation.
A 23.9 g piece of metal heated to 97.8 oC is placed in 52.4 g water at 21.9 oC. After the
metal is added, the temperature of the water rises to 29.9 oC. Calculate the specific heat of the
metal. Express your answer in the units of cal/goC.
3 answers
3783.63
37342
1 answer