0=N-m₁g => N = m₁g
0=T-F(fr) => T=F(fr)=μN= μ•m₁g
0=T-m₂g => T= m₂g
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μ•m₁g = m₂g
μ = m₂g/m₁g= 50/100 =0.5
A 100-N mass on a horizontal table is connected to a 50.0-N hanging mass over a
frictionless pulley. The two masses are moving at constant speed. What is the value of
the coefficient of kinetic friction between the table and the horizontal mass?
1 answer
1 answer