A 100-N force has a horizontal component of 80 N and a vertical component of 60 N. The force is applied to a box which rests on a level frictionless floor. The cart starts from rest, and moves 2.0 m horizontally along the floor. What is the cart's final kinetic energy?

Question

A 100-N force has a horizontal component of 80 N and a vertical component of 60 N.  The force is applied to a box which rests on a level frictionless floor.  The cart starts from rest, and moves 2.0 m horizontally along the floor.  What is the cart's final kinetic energy?

bobpursley · Accepted Answer

workin= horizontalforce*distance=80*2=160J final ke: 160 J