A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

Answer 1

F=ma

a=F/m

Answer 2

the answer is 2500

Answer 3

the answer is 98

Answer 4

A 100-kg crate, sliding on the floor, is brought to a stop by a 25-n force. What is the deceleration of the crate?

and the answer is 2500

Answer 5

since acceleration = Net force/ mass,
plug in 25 N for force and 100 kg for mass

you will get 0.25 m/s^2

Answer 6

actually, 0.25 with sig figs is 0.3 m/s^2, which is the correct answer.

Answer 7

i dont understand how this is to help me??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

Answer 8

It would definitely be 0.25 m/s, because you are finding the deceleration which is really another way to say something accelerates, and of something is accelerating we use the formula A=f/m. Divide 25 by 100 and you get 0.25