suspect 1000 kg not 100 kg but anyway
gravity down = 9.81 *100 = 981 N
acceleration down = v^2/r
Up force = F
so
981 - F = ma = 100 v^2/r
so
F = 981 - 100 (400)/200
= 781 N
but as you know if it is a real car I think 7810 N
A 100 kg car is traveling at 20m/s over the top of a circular hill as shown below. The radius of the circle is 200 m.
What force does the ground exert on the car at the top of the hill?
After reaching the top of the hill, the car descends a vertical distance of 20 m. What is the final velocity assuming that there is no friction?
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