Consider a road over a hill where the top is shaped like a circular bump. This circular arc has its center in the hill below. As a 1200 kg car rounds the top of a hill at a speed of 20.0 m/s, it very breifly loses contact with the pavement. What is the radius of this circular bump?

Answer 1

mass is irrelevant
when centripetal acceleration = 1 g, the vehicle leaves the road

Va = v^2/r = g

so r = v^2/g = 400/9.81

around 40 meters