A 100 g mass of aluminum at 100 deg C is placed in 100 g of water at 10 deg C. The final temperature of the mixture is 25 deg C. What is the specific heat of the aluminum?

Answer 1

q1-q2=0

q1=q2

q1=mc1∆t

q2=mc2∆t

Masses are the same so they aren't needed.

∆t=-75 C°, and c1=???? -75 will just be 75.

∆t=15 C°, and c2=4.186 J/g• C°

c1*(75 C)=(15 C)*(4.186 J/g• C°)

75c=62.79

c=62.79/75

c=0.8372 J/g• C°

Someone check my thinking.

Answer 2

mahesh sawant