Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)
Responses

30h=10
30 h equals 10

1,280+30h=0
1,280 plus 30 h equals 0

10−30h=0
10 minus 30 h equals 0

1,280−30h=0

Answer 1

To determine how long the water in the cooler will last, we need to set up an equation that reflects the amount of water in the cooler after a certain number of hours.

- We start with 1,280 ounces of water.
- Each hour, 30 ounces are removed.

Let \( h \) represent the number of hours the water will last. After \( h \) hours, the amount of water remaining can be expressed as \( 1280 - 30h \). We want to find the time \( h \) when this amount reaches zero because that will indicate that the water has run out. Therefore, we set up the equation:

\[
1,280 - 30h = 0
\]

Thus, the correct equation that shows how long the water in the cooler will last is:

\[
1,280 - 30h = 0
\]