A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.) (1 point) 10 - 30h = 0 1, 280 - 30h = 0 30h = 10 1, 280 + 30h = 0

To find out how long the water in the cooler will last, we start with the total amount of water in ounces and how fast the water is being used.

The total amount of water in the cooler is 10 gallons, which is equivalent to 1,280 ounces. The workers drink 30 ounces of water each hour.

We want to determine how many hours (h) it will take for the water to run out. We can set up an equation based on the water usage:

1,280 ounces - (30 ounces/hour * h hours) = 0

We can rearrange this equation to isolate h:

1,280 - 30h = 0

Thus, the correct equation is:

**1,280 - 30h = 0**

This means the answer is the second option listed.